作者a27281591 (皮皮)
看板Physics
标题[题目] diffraction grating 绕射光栅
时间Tue Jan 5 03:15:22 2010
[领域] 光学 diffraction grating
[来源] physics for scientists and engineers 2e (randall d. knight)
课本习题
[题目] Light passes through a 240 lines/mm grating and is observed on a
1.2-m-wide screen located 1.4m behind the grating. Three bright fringes
are seen on both sides of the central maximum.
What are the minimum and maximum possible values of the wavelength ?
[瓶颈]
d=10^-3/240=4.17*10^-6 m=3 L=1.4 y=1.2/2=0.6=1.4*tanθ
算出θ 带入sinθ=mλ/d 求出λ=547.6nm 为最大值
可是最小值怎麽算都比最大值大 @@ 拜托强者了~
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◆ From: 163.25.118.131
※ 编辑: a27281591 来自: 163.25.118.131 (01/05 03:38)
※ 编辑: a27281591 来自: 163.25.118.131 (01/05 11:51)
1F：推 colorya2001:你有答案吗? 我算出来最小值是最大值波长的3/4 01/05 12:12
2F：→ a27281591:没有 @@ 我试试看 01/05 13:30
3F：→ a27281591:是正解!!! 01/05 13:40