作者nem2050 (nem2050)
看板Physics
标题[问题] 一题力学问题~~
时间Mon Nov 23 22:28:13 2009
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Two masses (m) are connected by a thin rod of length L.
The whole system is suspended by two strings at both
ends as shown in the folloing diagram.
What is the tension of the left string acting on the
mass-rod system immediately after the right string is cut?
a) Consider the case of a massless rod. Solve the problem
by using two different methods.
(Certainly, make sure you get the same answer!)
b) Extend one of your calculations to the case that the
mass of rod also equals to m, which is uniformly distributed.
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我自己的想法是: 当细绳还没被剪掉的时後两条绳的张力各为 mg
剪掉以後 左绳的张力应该要大於mg
但是在 剪掉右绳的"瞬间" 左绳的张力应要等於 mg
因为如果大於 mg 那右边质量传递力的速度就是 无限大 不合理
不知道我这样的想法对不对?
这题我想了好久都没一个好的解法 这题目可以用
Lagrangian Dynamics来解吗? 我该从那下手?
请版上的高手指教 !!
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◆ From: 122.116.1.165
1F:推 xhole:这题很有名XD 记得是UCB的普物考题 11/23 22:59
2F:推 nightkid:左绳张力=mg喔 >.^ 11/23 23:09
3F:推 nightkid:我想...这应该是林留的期中考题吧... 11/23 23:27
4F:推 xhole:林留还有在教普物喔XDDD 11/23 23:37
5F:推 nightkid:这是古典物理啦~研究所的课 11/24 00:14
6F:推 xhole:XD 以前林留的普物课有讲过这题 他好像是说这是他去美国 11/24 00:41
7F:→ xhole:念博士的时候教授问的题目 11/24 00:41
8F:推 colorya2001:我是根据移动及转动来列式 算出左侧绳张力(1) 0 mg 11/24 13:19
9F:→ colorya2001:(2)15/32mg 不晓得对不对! 你有答案吗? 11/24 13:20
10F:→ nem2050:我没有答案耶~ (1)0 mg 是怎麽样算的阿 !! 11/25 21:46