作者grind (无边落木)
看板Physics
标题Re: [问题] 有关helmholtz equation...
时间Fri Apr 20 05:03:06 2007
[(▽^2)+k^2]U(r)=0, 此处的 ▽^2 = (d^2)/dx^2 + (d^2)/dy^2 + (d^2)/dz^2
定义 ▽t^2 = (d^2)/dx^2 +(d^2)/dy^2
[(▽^2)+k^2] * U(r) = 0
=> [(▽^2)+k^2] * A(r)exp(-ikz) = 0
=> [ ▽t^2 +
(d^2)/dz^2 + k^2 ] * A(r)exp(-ikz) = 0
=> ▽t^2 * A(r)exp(-ikz) + k^2 * A(r)exp(-ikz) +
(d^2)/dz^2 * A(r)exp(-ikz) = 0
见注1
▽t^2 * A(r)exp(-ikz) + k^2 * A(r)exp(-ikz) +
{ -i2k * dA/dz + d^2/dz^2 - k^2 * A } * exp(-ikz) <----------------|
= 0 |
|
▽t^2 * A(r) +
k^2 * A(r) - i2k * dA/dz + d^2/dz^2 * A -
k^2 * A = 0 | |
▽t^2 * A(r) - i2k * dA/dz + d^2/dz^2 * A = 0 |
|
(对不起 我只会算数学..d^2/dz^2项 消不掉..Orz) |
|
|
|
注1 |
|
d/dz * A(r)exp(-ikz) =
exp(-ikz) * dA/dz +
A * (-ik) * exp(-ikz) |
|
(d^2)/dz^2 * A(r)exp(-ikz) |
= d/dz [
d/dz * A(r)exp(-ikz)] |
=
(-ik) * exp(-ikz) * dA/dz + exp(-ikz) * (d^2)/dz^2 + |
dA/dz * (-ik) * exp(-ikz) + A * (-ik) * (-ik) * exp(-ikz) |
= { -i2k * dA/dz + d^2/dz^2 * A - k^2 * A } * exp(-ikz) -------------|
※ 引述《bigbvd2001 (重新开始)》之铭言:
: 小弟有疑惑的地方是在
: Paraxial Helmholtz equation
: (▽^2)A-i2k(dA/dz)=0
: (附注:(dA/dz)是A对z偏微分,此处的▽=(d^2)/dx^2 +(d^2)/dy^2)
: 课本上说导证的方法是利用paraxial wave:U(r)=A(r)exp(-ikz)
: 将其带入Helmholtz equation :[(▽^2)+k^2]U(r)=0
: 并藉由(dA/dz)<<kA 以及 [(d^2)A]/dz^2 <<k^A
: 可以得到Paraxial Helmholtz equation
: 可是我怎麽算都只能求得(▽^2)A+2(k^2)A=0
: 麻烦各位帮忙解惑,感激不尽!!
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1F:推 bigbvd2001:感谢你!!!:) 04/20 09:01