作者t90766 (Feng)
看板trans_math
標題[積分] 90政大資管
時間Thu Jul 10 08:48:09 2008
x
Let f(x)=∫ e^[(t-1)/t^2] dt, x≧1. Find the interval(s)
1
where f is concave upward, and the interval(s) where f is concave downward.
微了一次還是e...要怎麼解呀= =???
先感謝各路高手!!!
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 220.132.175.253