作者t90766 (Feng)
看板trans_math
标题[积分] 90政大资管
时间Thu Jul 10 08:48:09 2008
x
Let f(x)=∫ e^[(t-1)/t^2] dt, x≧1. Find the interval(s)
1
where f is concave upward, and the interval(s) where f is concave downward.
微了一次还是e...要怎麽解呀= =???
先感谢各路高手!!!
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