作者sato186 (銀色轟炸機)
看板Math
標題Re: [微分] 勘根定理
時間Mon Mar 7 00:04:29 2011
※ 引述《immortal8305 (immortal)》之銘言:
: ※ [本文轉錄自 trans_math 看板 #1DSwZ0RD ]
: 作者: immortal8305 (immortal) 看板: trans_math
: 標題: [微分] 勘根定理
: 時間: Sun Mar 6 23:31:09 2011
: Let p(x) be a polynomial of odd degree with real coefficient.Then equation
: p(x)=0 has at least one real root.prove this.
n n-1
Set p(x) = a x + a x + ... + a x + a has odd degree.
n n-1 1 0
WLOG, assume that a > 0. Let
M = max {|a |, |a |, |a |, |a |, 1.}.
n
n n-1 1 0
1
Since a > 0, there exists a positive integer N such that
a > ── .
n
n N
n n-1 n-2
So p(kM)
≧ a (kM) – M(kM) – M(kM) – ... – M(kM) – M =
n
n n
n n n k -1 n n n k -1 1 n
a k M – M ────
≧ a k M – M ──── > (a – ──) k
n k-1 k N k N
for
k-1 ≧ N. So
p( (N+1)M ) > 0. Similarly,
p( -(N+1)M ) < 0.
By intermediate value theorem, p(c) = 0 for some c in
( -(N+1)M, (N+1)M ).
--
翩若驚鴻 婉若游龍 榮曜秋菊 華茂春松
髣彿兮若輕雲之蔽月 飄颻兮若流風之迴雪
遠而望之 皎若太陽升朝霞 迫而察之 灼若芙蕖出淥波
襛纖得衷 脩短合度 肩若削成 腰如約素 延頸秀項
皓質呈露 芳澤無加 鉛華弗御 雲髻峨峨 脩眉聯娟
丹脣外朗 皓齒內鮮 明眸善睞 靨輔承權 瑰姿豔逸 儀靜體閑 柔情綽態 媚於語言 奇服曠世 骨像應圖
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 111.242.1.32
1F:推 immortal8305:謝謝 03/07 12:58