※ 引述《personhuang (Person)》之銘言： : 請問一下 記憶體方面的概念 : 講義上有寫 heap 是pointer 的content : stack 是local variable : 那reference 是放在哪 內容是在哪 由reference的對象決定？ "reference" is just an alias in the "symbol table". It does not take any space in either the heap or stack memory. : 那對於array來說 array 他內容是放heap? It depends on whether it is a local array variable. For example, ---------- void f() { int arr[10]; } --------- "arr" is a local variable in "f()" so it will reside in the stack memory with size = sizeof(int) * 10. Another example, ------------ void g() { int* arr = new int[10]; } ------------ "arr" is STILL A LOCAL VARIABLE in "f()". However, it will only take 4 bytes in the stack memory (storing the address of "new int[10]"). The memory it points to (total sizeof(int) * 10 [註 (i)] ) will reside in the heap memory. : 還有能否解釋 如果是單純因為結束f() 因此i位址值釋放 而爛掉 那為何每次爛的一樣 : 還有 (v) 有人overlap 有人不會overlap 是因為什麼 This is a machine/platform dependent issue. : 不知道有沒有描述的清楚 謝謝指導 [Hint] Please note that when a function is called, it will take up some memory in the stack memory. They are for the "returned address", "parameters", etc. [註 1] Actually it will take 4 bytes more of memory ==> to store that the size of array is "10". We will talk about the in the "Memory Management" unit. --

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