※ 引述《personhuang (Person)》之铭言： : 请问一下 记忆体方面的概念 : 讲义上有写 heap 是pointer 的content : stack 是local variable : 那reference 是放在哪 内容是在哪 由reference的对象决定？ "reference" is just an alias in the "symbol table". It does not take any space in either the heap or stack memory. : 那对於array来说 array 他内容是放heap? It depends on whether it is a local array variable. For example, ---------- void f() { int arr[10]; } --------- "arr" is a local variable in "f()" so it will reside in the stack memory with size = sizeof(int) * 10. Another example, ------------ void g() { int* arr = new int[10]; } ------------ "arr" is STILL A LOCAL VARIABLE in "f()". However, it will only take 4 bytes in the stack memory (storing the address of "new int[10]"). The memory it points to (total sizeof(int) * 10 [注 (i)] ) will reside in the heap memory. : 还有能否解释 如果是单纯因为结束f() 因此i位址值释放 而烂掉 那为何每次烂的一样 : 还有 (v) 有人overlap 有人不会overlap 是因为什麽 This is a machine/platform dependent issue. : 不知道有没有描述的清楚 谢谢指导 [Hint] Please note that when a function is called, it will take up some memory in the stack memory. They are for the "returned address", "parameters", etc. [注 1] Actually it will take 4 bytes more of memory ==> to store that the size of array is "10". We will talk about the in the "Memory Management" unit. --

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