作者ComeonLuLuLu (卢彦勳加油)
看板Physics
标题[题目] 线电荷 某点的电压
时间Wed Mar 30 21:03:56 2011
电学
以知线电荷密度 求某点对某段之电压
A charge of uniform density (0.80 nC/m) is distributed along the x axis from
the origin to the point x = 10 cm. What is the electric potential (relative
to zero at infinity) at a point, x = 18 cm, on the x axis?
是要用积分吗? 可是r^-1次方 积分变ln 要怎麽算= =
18
我的想法是 S (kq/r)
8 但在计算上有困难
18
=>Kq S r^-1 天哪 我没算过ln 有区域的 怎算
8
9*10^9*8*10^-11*(ln18-ln8)= 0.583869756
答案怪怪的
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 120.101.34.119
※ 编辑: ComeonLuLuLu 来自: 120.101.34.119 (03/30 21:09)
1F:推 jerry78424:有ln就按计算机嘛 03/30 21:08
※ 编辑: ComeonLuLuLu 来自: 120.101.34.119 (03/30 21:11)
2F:推 jerry78424:ln(18)-ln(8) 03/30 21:18
可以直接这样算?
※ 编辑: ComeonLuLuLu 来自: 120.101.34.119 (03/30 21:21)
※ 编辑: ComeonLuLuLu 来自: 120.101.34.119 (03/30 21:26)
3F:推 nightkid:阿就是ln(18) - ln(8) = ln(18/8) 03/30 21:52
4F:推 HDT:ln就是log啊 03/30 22:06
5F:推 j0958322080: e 03/30 22:49
6F:→ Entropy1988:lnX = e的几次方是X 。 其实就是log 03/31 20:52