作者Qmmmmnn (Qmmmmmmmmm)
看板Physics
标题[题目] 电子学简单例题
时间Mon Sep 20 00:50:20 2010
[领域]电子学 (题目相关领域)
[来源]smith p20 ch1 (课本习题、考古题、参考书...)
[题目]
An amplifier operating from a single 15-V supply provides a 12-V peak-to-peak
sine-wave signal to a 1-kΩ load and draws negligible input current from
the signal source. The dc current drawn from the 15-V supply is 8mA.
What is the power dissipated in the amplifier, and what is the amplifier
efficiency?
[瓶颈] (写写自己的想法，方便大家为你解答)
从题目可得
Vcc = 15(V)
Icc = 8(mA)
Vo = 12/√2(V)
Io = 12/√2(mA)
RL = 1kΩ
因为能量守恒，所以ViIi + 15*8 = (12/√2)(12/√2) + P(dis)
但是我不知道Vi跟Ii...=.="
所以我不知道该怎麽算....
很怕是自己看错题目..@@"
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