: 我有再看了课本 但不是很懂= = : 老师上课有讲一个简单例题 : 半径a跟b的同心圆壳 算出来的C11=-C12=-C21=/=C22 : 最後就取C=C11 这怎麽去决定? : C11=ab/(b-a) C12=C21=-ab/(b-a) C22=b^2/(b-a) the coefficients Cij are capacities or capacitances while Cij,i=/=j,are called coefficients of induction. thecapacitance of a conductor is therefore the total charge on the conductor when it is maintained at unit potential, all other of conductors beingheld at zero potential. sometimes the capacitance of a system of conductors is also defined. for example, the capacitance of two conductors carrying equal and opposite charges in the presence of other grounded conductors is defined as the ratio of the charge on one conductor to the potential difference between them. the equations Qi=summation CijVi can be used to express this capacitance in terms of the coefficients Cij 如果没错你应该是说这段吧 可是除了提到V=V1-V2 我不太了解哪里叙述可以导出你提到的C=det(Cij)/sum(Cij) 是我英文不好吗~"~ -- 朱子老师一起来提点一下嘛 我的电磁学因你获益良多耶 --

※ 发信站: 批踢踢实业坊(ptt.cc) ◆ From: 114.42.215.151 ※ 编辑: mouwat 来自: 114.42.215.151 (11/18 19:47)