作者mqazz1 (无法显示)
看板Math
标题[线代] eigenvalue
时间Thu Jul 28 15:26:28 2011
[ 4 1 0 0 1 ] [cos( θ+ψ)]
[ 1 4 1 0 0 ] [cos(2θ+ψ)]
B = [ 0 1 4 1 0 ] x = [cos(3θ+ψ)]
[ 0 0 1 4 1 ] [cos(4θ+ψ)]
[ 1 0 0 1 4 ] [cos(5θ+ψ)]
[b]
[0]
Bx-ax = [0], a,b,c属於R, where(a,b,c)=? (express in terms of θ and ψ)
[0]
[c]
请问这题要怎麽解呢?
谢谢
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