作者JohnMash (Paul)
看板Math
标题Re: [线代] eigenvalue
时间Wed Jul 6 22:21:41 2011
※ 引述《mqazz1 (无法显示)》之铭言：
: [1] [5]
: [2] [4] [v^T]
: u = [3] v = [3] A = I + [u v][u^T]
: [4] [2]
: [5] [1]
: find all the eigenvalue of A
|u|^2=|v|^2=α=55,(u'.v)=(v'.u)=β=35, where ' means transpose
A=I+u.v'+v.u'
w1,w2,w3,u,v are a basis
such that wi⊥u, wi⊥v for i=1,2,3
A.wi=wi, i=1,2,3
A.(u+v)=u+v+u.v'.(u+v)+v.u'.(u+v)
=u+v+(v'.u)u+αu+αv+(u'.v)v
=(1+α+β)(u+v)=91(u+v)
A.(u-v)=u-v+u.v'.(u-v)+v.u'.(u-v)
=u-v+(v'.u)u-αu+αv-(u'.v)v
=(1-α+β)(u-v)=-19(u-v)
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◆ From: 112.104.170.71
※ 编辑: JohnMash 来自: 112.104.170.71 (07/06 22:23)
1F：推 mqazz1 :谢谢 另外我还有一些疑问 PO在原文上..不知能否请问 07/06 23:07