作者IdfaLL0803 (:D)
看板Math
标题[线代] Jordan canonical form
时间Sun Jun 19 10:32:54 2011
想请问大家 怎麽算 @@"
1. Find generalized eigenvectors and a Jordan canonical form
for the linear operator T: P2(R) → P2 (R) defined by
T(f(x)) = 2f(x) - f'(x)
2. Find generalized eigenvectors and a Jordan canonical form
for the matrix A = — —
| 2 -1 0 1 |
| 0 3 -1 0 |
| 0 1 1 0 |
| 0 -1 0 3 |
— —
麻烦了 > <
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1F:推 calvin4 :1. (1)找出P2(R)的basis;(2)把basis的每个向量都丢 06/19 12:00
2F:→ calvin4 :到T里面去算一算;(3)写出T的矩阵表示法;(4)算这个 06/19 12:01
3F:→ calvin4 :矩阵的eigenvectors跟Jordan form。 06/19 12:03
4F:→ calvin4 :至於怎麽算……建议你先翻翻课本。 06/19 12:03