※ 引述《lorandy (D)》之铭言： : 1. When a mixture of 3-phosphoglycerate and 2-phosphoglycerate is incubated : at 25℃ with phosphoglycerate mutase until equilibrium is reached, the : final mixture contains six times as much 2-phosphoglycerate as : 3-phosphoglycerate. Which one of following statements is most nearly correct : ? （R=8.315J/mol‧K；T=298K） : A) △G’0 is －1.44 kJ/mol : B) △G’0 is zero : C) △G’0 is ＋12.7 kJ/mol : D) △G’0 is incalculably large and positive : E) △G’0 cannot be calculated from the information given 这一题应该不用真的去算他，虽然可以算。 因为公式为: △G’0= -RTlnKeq ，但是3-phosphoglycerate 是substrate and 2-phosphoglycerate 是product ，後者量是前者6倍。 lnX 会是>0的数值，所以△G’0 是负值，且ln 後的数值不大， 所以就"看"出答案是 A~ : 2. All of the following contribute to the large, negative, free-energy change : upon hydrolysis of "high-energy" compounds except： : A) electrostaatic repulsion in the reactant : B) low activation energy of forward reaction : C) stabilization of products by extra resonance forms : D) stabilization of products by ionization : E) stabilization of products by solvation 照题意，指的是反应非常倾向於生成物，且反应物具极大能量(=不稳定，易反应) 所以A,C,D,E都是可能的解释， 而B相对就是错的，因为是反应物本身的不稳定 高能量，才造成反应易於进行，非低活化能~ 所以B错~ 希望还能够回答到您的疑问~ ps 小弟也是今年考生XD : 以上两题答案为 1.A 2.B 不过我不知道为甚麽 : 有没有人可以稍微解释一下呢? 谢谢大家~~ --

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