p.23 #11 (同p.19 #11) 这题很狠喔 老师没教就sudden death了 11. 父母的任何一方为家族性结肠息肉症患者，则其子女罹患机率为 ANS: (C)50% 详解：http://ghr.nlm.nih.gov/condition/familial-adenomatous-polyposis When familial adenomatous polyposis results from mutations in the APC gene, it is inherited in an autosomal dominant pattern, which means one copy of the altered gene in each cell is sufficient to cause the disorder. In most cases, an affected person has one parent with the condition. When familial adenomatous polyposis results from mutations in the MUTYH gene, it is inherited in an autosomal recessive pattern, which means both copies of the gene in each cell have mutations. Most often, the parents of an individual with an autosomal recessive condition each carry one copy of the mutated gene, but do not show signs and symptoms of the condition. 所以总共有四种情况 APC mutation - 体联显性 1) AA x aa 100% 2) Aa x aa 50% MUTYH mutation - 体联隐性 3) aa x Aa 50% 4) aa x AA 0% 所以答案还是50% ya!!! --

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