作者LuisSantos (^______^)
看板trans_math
標題Re: [微分] 94東吳經濟
時間Wed Dec 5 18:49:23 2007
※ 引述《bitchdog (PEaCE)》之銘言:
: f(x)=cos [ sin(tanx)], find f'(x)
f(x) = cos[sin(tanx)]
d
f'(x) = (-sin[sin(tanx)])(----(sin(tanx)))
dx
d
= (-sin[sin(tanx)])(cos(tanx))(----(tanx))
dx
= (-sin[sin(tanx)])(cos(tanx))((secx)^2)
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