※ 引述《supsymmetry (supsymmetry)》之銘言： : We know in baseband, signal bandwidth equals (1+r)/2 times signal sampling r : ate (PAM) or equals (1+r)/2 times signal bit rate (PCM) where r is the raise : d cosine filter roll-off factor. : And according to Nyquist sampling theorem, the sampling rate is twice of hig : hest signal frequency. : So the bandwidth is (1+r) times the highest signal frequency (PAM). ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 因為bandwidth是(1+r)/2*R_s,而R_s=2f_H,所以,bandwidth=(1+r)f_H : Does this hold for passband? : It seems as if W=M*R_{s}=M/T_{s} for MFSK where R_{s} is the symbol rate and : T_{s} is the symbol time duration. : How about the relationship between highest frequency and bandwidth of passba : nd signaling? In another word, what's the sampling theorem of passband signa : ling? --

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