Sorry for the wrong correction about this question. I thought another story about this question yesterday. Actually, the type of player 1 and player 2 does not have to be independent. You can calculate the conditional probability from the disjoint distribution matrix, and get the results which I derived yesterday. TA Jack ※ 引述《Jackliu2619 ()》之銘言： : I found that the disjoint distribution matrix does not have enough information : for you to calculate the expected payoffs for each player under different : situations. Therefore, I have to add some description of the question: : (1) Assume the type of player 1 and player 2 are independent : (2) Player 1 is type 1 with the probability 0.5 : Player 2 is type 1 with the probability 0.4 : Then you can check the answer by yourselves. : TA Jack --

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