各位大大好 小弟最近開始學django,跟著“it's django-用python迅速打造web應用”學習 但在建立modle跟資料庫同步時遇到錯誤訊息,而我用的環境是python2.7＋django1.8 django.db.utils.OperationalError: table restaurants_food__new has no column named name 但我並沒有建立叫 restaurants_food__new 的 table 啊？？ 底下是我的models.py 內容 from django.db import models # Create your models here. class Restaurant(models.Model): name = models.CharField(max_length=20) phone_number = models.CharField(max_length=15) address = models.CharField(max_length=50, blank=True) class Food(models.Model): name = models.Field(max_length=20) price = models.DecimalField(max_digits=3,decimal_places=0) comment = models.CharField(max_length=50, blank=True) is_spicy = models.BooleanField(default=False) restaurant = models.ForeignKey(Restaurant) 底下是完整錯誤訊息 -> python manage.py migrate restaurants 0001 Operations to perform: Target specific migration: 0001_initial, from restaurants Running migrations: Rendering model states... DONE Applying restaurants.0001_initial...Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Python/2.7/site-packages/django/core/management/__init__.py", line 338, in execute_from_command_line utility.execute() File "/Library/Python/2.7/site-packages/django/core/management/__init__.py", line 330, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.7/site-packages/django/core/management/base.py", line 393, in run_from_argv self.execute(*args, **cmd_options) File "/Library/Python/2.7/site-packages/django/core/management/base.py", line 444, in execute output = self.handle(*args, **options) File "/Library/Python/2.7/site-packages/django/core/management/commands/migrate.py", line 221, in handle executor.migrate(targets, plan, fake=fake, fake_initial=fake_initial) File "/Library/Python/2.7/site-packages/django/db/migrations/executor.py", line 110, in migrate self.apply_migration(states[migration], migration, fake=fake, fake_initial=fake_initial) File "/Library/Python/2.7/site-packages/django/db/migrations/executor.py", line 148, in apply_migration state = migration.apply(state, schema_editor) File "/Library/Python/2.7/site-packages/django/db/migrations/migration.py", line 115, in apply operation.database_forwards(self.app_label, schema_editor, old_state, project_state) File "/Library/Python/2.7/site-packages/django/db/migrations/operations/fields.py", line 62, in database_forwards field, File "/Library/Python/2.7/site-packages/django/db/backends/sqlite3/schema.py", line 179, in add_field self._remake_table(model, create_fields=[field]) File "/Library/Python/2.7/site-packages/django/db/backends/sqlite3/schema.py", line 147, in _remake_table self.quote_name(model._meta.db_table), File "/Library/Python/2.7/site-packages/django/db/backends/base/schema.py", line 111, in execute cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/utils.py", line 79, in execute return super(CursorDebugWrapper, self).execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/utils.py", line 64, in execute return self.cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/utils.py", line 97, in __exit__ six.reraise(dj_exc_type, dj_exc_value, traceback) File "/Library/Python/2.7/site-packages/django/db/backends/utils.py", line 64, in execute return self.cursor.execute(sql, params) File "/Library/Python/2.7/site-packages/django/db/backends/sqlite3/base.py", line 318, in execute return Database.Cursor.execute(self, query, params) django.db.utils.OperationalError: table restaurants_food__new has no column named name 不曉得有沒有人也有遇到相同的問題 謝謝 --

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