我佛心來著，其實是想賺P幣 發一發離散第一章的解答 ============================================================================== 1.1 & 1.2 (8+6)x(4+6+2) 9(a) =168 [(8+6)x(4x3)]x[6x(6x3)] (b) =18144 [8x(6x3)]x[6x(1x3)]x[(8+6)x(4x3)] (c) =73156608 8!/3! 20(a) =6720 6! (b) =720 12!/(4!3!2!3!) 23 =27720 (2+1+7)!/(2!7!) 27(a) =360 (7+1+2)!/(7!2!) (b) =360 請見原文書的解答 (c) 請見原文書的解答 12x1+6x2+8x3 28(a) =48 和規則 (b) 和規則 12x6x8 29(a) =576 積規則 (b) 積規則 2^10 33(a) =1024 3^10 (b) =59049 注意：此題中文本翻譯有誤 8!/4 36(a) =10080 (b) =我忘了算 (16C10)x(10!/10)x(6!/6) 37 =348713164800 ============================================================================== 1.3 6+(6C2)+(6C3)+(6C4)+(6C5)+1=2^6-1 4(a) =63 6C3 (b) =20 (6C2)+(6C4)+1 (c) =31 (13C5)x4 8(a) =5148 48C1 (b) =48 13x(48C1) (c) =624 (4C3)x(4C2) (d) =24 (4C3)x(4C2)x13 (e) =312 (4C3)x13x(4C2)x12 (f) =3744 (4C3)x13x(48C2) (g) =58656 (13C2)x(4C2)^2x(44C1) (h) =123552 15C2 15(a) =105 25C3 (b) =2300 =2300 25C4 =126500 8C3 20(a) =56 8C4 (b) =70 忘了算 (c) =忘了算 nC3 21(a) =(nC3) 2邊 1邊 (b) =(nC3)-n-n(n-4) , 其中 n>=4 4!/2! 25(a) =12 4!/2! (b) =12 -2x(4!/2!) (c) =-24 -2x9x(4!/2!) (d) =-216 8x3x4x[8!/(3!2!2!)] (e) =161280 ============================================================================== 1.4 35C32 7(a) =6545 31C28 (b) =4495 11C8 (c) =165 1 (d) =1 43C40 (e) =12341 (31C28)-(6C3) (f) =4475 (8C6)x(34C31) 18(a) =167552 (5C3)x(34C31) (b) =59840 23C4 19 =8855 證明略 22 證明 證明略 23(a) 證明 證明略 (b) 證明 有錯請在回文中提醒，才能訂正 -- 請不要從PTT外流到其他地方 尤其是facebook 有看到的也別說出去 --

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