作者suhorng ( )
看板NTU-Exam
標題[試題] 100下 陳健輝 離散數學 第二次期中考
時間Mon May 28 13:21:27 2012
課程名稱︰離散數學
課程性質︰資訊系選修
課程教師︰陳健輝
開課學院:電資學院
開課系所︰資訊系
考試日期(年月日)︰2012/05/28
考試時限(分鐘):120
是否需發放獎勵金:是
(如未明確表示,則不予發放)
試題 :
Examination #2
(範圍: Algebra)
1. Prove that if n^2 is even, then n is even, based on the logic of p→q <=>
┐q → ┐p. (10%)
2. The following are some binary relations on A = {1, 2, 3, 4}.
R_1 = {(1,1), (2,2), (3,3), (4,4), (1,2), (1,3), (1,4), (4,2), (4,3)}.
R_2 = {(1,1), (2,2), (3,3), (4,4), (1,2), (2,1), (1,4), (2,3), (4,2)}.
R_3 = {(1,1), (4,4), (1,2), (1,3), (1,4), (2,3), (4,2), (4,3)}.
R_4 = {(1,2), (1,3), (1,4), (2,3), (4,2), (4,3)}.
R_5 = {(1,1), (2,2), (3,3), (4,4), (1,2), (1,3), (1,4), (2,3), (4,2), (4,3)}.
(a) Which are total orderings? (3%)
(b) Which are partial orderings, but not total orderings? (3%)
(c) For each of (b), list all topological orders on A. (4%)
3. Let A = {1,2,3,4,5,6,7}, and define a binary relation R as follows:
(x,y)∈R if and only if 3 | (x-y).
(a) Show that R is an equivalence relation on A. (6%)
(b) Determine the equivalence classes induced by R. (4%).
4. Show that the following two logic circuits are functionally equivalent,
i.e., they produce the same output, when fed with the same input. (10%)
_ _ _ _ _ _ _ _ _
f(w,x,y,z) = w x y z + w x y z + w x y z + w x y z + w x y z
_ _ _
+ w x y z
_ _ _ _ _ _
f(w,x,y,z) = w x z + w x y + w x y + w x z
(原圖請參閱老師講義 p.67 以及 p.69 上圖)
http://inrg.csie.ntu.edu.tw/discrete2012/course/Part_2_Algebra.pdf
5. The following two tables make (R, + .‧) into a ring, where R = {s,t,x,y}.
(a) What is the zero of R? (2%)
(b) What is the additive inverse of t? (2%)
(c) Is R communicative? Why? (2%)
(d) Does R have a unity? Why? (2%)
(e) Find all proper zero divisors of R. (2%)
+ | s t x y ‧| s t x y
----+-------------- ----+--------------
s | y x s t s | y y x x
t | x y t s t | y y x x
x | s t x y x | x x x x
y | t s y x y | x x x x
| |
6. The following is a proof for the fact that a finite integral domain
(R, + ,‧) is a field.
Suppose R = {d_1, d_2, ..., d_n}, where d_i's are distinct.
Let a∈R and a≠z.
We have a‧d_1, a‧d_2, ..., a‧d_n all distinct, and hence
{a‧d_1, a‧d_2, ..., a‧d_n} = R.
Since u∈R, we have u = a‧d_k = d_k‧a for some k, i.e.
a^{-1} = d_k∈R.
(1) Why is R = {d_1, d_2, ..., d_n} supposed? (2%)
(2) Why are a‧d_1, a‧d_2, ..., a‧d_n all distinct? (3%)
(3) Why {a‧d_1, a‧d_2, ..., a‧d_n} = R? (2%)
(4) Why is the proof complete, as a^{-1} = d_k∈R is derived? (3%)
7. Find (1) [21]^{-1} in Z_{65} and (2) 1 <= x <= 64 so that [40]‧[x] = [0]
in Z_{145}. (10%)
┌ a 0 ┐ |
8. Let S = { │ │ | a∈R }, where R is the set of real numbers. Then,
└ 0 a ┘ |
S is a ring under matrix addition and multiplication. Prove that R is
isomorphic to S. (10%)
9. Suppose that ( G ,‧) is a group with a generator a and |G| = n. The
following is an incomplete proof for that a^k is also a generator for G
if and only if gcd(k,n) = 1, where k is a positive integer. Please
provide the missing parts, i.e., "--- (1) ---" and "--- (2) ---". (10%)
(if) For any b∈G. Suppose b = a^r for some integer r.
gcd(k,n) = 1 => ks + nt = 1 for some integers s and t
=> b = a^4 = a^{r(ks+nt)} = --- (1) ---
i.e., b can be generated by a^k.
(only if) G = <a^k> => a = (a^k)^s for some integer s
=> a^{1 - ks} = e
=> --- (2) ---
=> gcd(k,n) = 1
10. Let G be a group with subgroups H and K. If |G| = 660, |K| = 66, and
K ⊂ H ⊂ G, what are the possible values for |H|? (10%)
--
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◆ From: 140.112.30.81
1F:推 peter506g :看到這帳號先拜總沒錯<(_ _)> 05/28 14:13
2F:推 chichiwater :好快 原本想來PO的說 <(_ _)> 05/28 17:12
用pietty打字好蛋疼...
※ 編輯: suhorng 來自: 61.217.33.159 (05/28 19:41)
3F:推 cebrusfs :朝聖 05/29 01:43
4F:推 roymustang :看到原PO不拜說不過去<(_ _)> 05/31 08:17
5F:推 s864372002 :看到原PO不拜說不過去<(_ _)> 05/31 11:33
6F:推 awy777 :看到原PO不拜說不過去<(_ _)> 06/05 22:45
7F:推 kevin4314 :看到原PQ不拜說不過去<(_ _)> 06/05 23:20
8F:推 coldman519 :看到原PQ不拜說不過去<(_ _)> 06/05 23:29
9F:推 yanghowa :看到原PO不拜說不過去<(_ _)> 06/06 00:14