作者angie0716 (大寶與困寶)
看板GMAT
標題[計量] OG的168與175題
時間Tue Jul 22 16:35:35 2008
題目是這樣的
168.An airline passenger is planning a trip that involves three connecting
flights that leaves from Airports A, B, and C,respectively. The first flight
leaves Airport A every hour, beginning at 8:00 a.m., and arrives at Airport
B 2 and 1/2 hours later. The second flight leaves Airport B every 20 minutes,
beginning at 8:00 a.m., and arrives at Airport C 1 and 1/6 hours later. The
third flight leaves Airport C every hour, beginning at 8:45 a.m. What is the
least total amount of time tha passenger must spend between flights if all
flights keep to theur schedules? Ans:1 hr 15 minutes
這題其實題目有點看不太懂..外加解答看的霧煞煞..
另一題175.
A square countertop has a square tile inlay in the center, leaving an untiles
strip of uniform width around the tile. If the ratio of the tiled area to the
untiled area is 25 to 39, which of the following could be the width, in inches
, of the strip?
Ans:1.3.4
這題也是題目看不太懂@@....麻煩大家了
謝謝:)
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1F：推 seawolfssn:168. A->B->C 三段航程聯票 就是A出發到B B出發到C 07/22 16:53
2F：→ seawolfssn:請問旅客所花費的"候機"時間? 07/22 16:54
3F：→ seawolfssn:航站A 每小時一班飛機飛B 07/22 16:55
4F：→ seawolfssn:航站B 每20分鐘一班飛機飛C 07/22 16:56
5F：→ seawolfssn:假設蝙蝠俠 在航站A搭乘早上8:00AM經過2 1/2小時到航B 07/22 16:59
6F：→ seawolfssn:他到達航站B 時間為10:30 所以蝙蝠俠比須等待 10分鐘 07/22 17:00
7F：→ seawolfssn:搭乘10:40的飛機到航站C 07/22 17:00
8F：→ seawolfssn:蝙蝠俠花了1 1/6到達航站C 到達航站C時間為11:50 07/22 17:02
9F：→ seawolfssn: 小時 07/22 17:02
10F：→ seawolfssn:然後蝙蝠俠必須等12:45離開C航廈的班機 07/22 17:04
11F：→ seawolfssn:因為C航站從 8:45起 每一小時發一班飛機 07/22 17:05
12F：→ seawolfssn:所以蝙蝠俠必須等待 55分鐘的候機時間~ 07/22 17:05
13F：→ seawolfssn:所以 10 + 55 = 65 = 1 hour 5 minutes 07/22 17:06
14F：→ seawolfssn:*補充* A->B->C 三段航程聯票=A到B B到C C再到某地! 07/22 17:08