作者keith291 (keith)
看板trans_math
标题Re: [积分] 崇积分
时间Wed Jun 24 00:06:03 2009
※ 引述《qqazw5789tw (嘟嘟)》之铭言：
: ∫∫ xye^yx^2dA R=[0,1]*[0,2]
: R
2 1 2 1
∫∫ xye^(yx^2) dxdy =∫ (1/2)e^(yx^2)│ dy
0 0 0 0
2
= (1/2)∫ e^y -1 dy
0
=(1/2)(e^2-3)
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