A 26 foot ladder is placed against a wall. Id the top of the ladder is sliding down the wall at 2 feet per second,at what rate is the bottom of the ladder chanfinf when the bottom od the ladder is 10 feet aeay from the wall? 题目大致上是说一个梯子长 26 foot (为feet之复数) 靠在一座墙上 梯子的顶部每秒钟向下滑落2 feet 请问当梯子的底部离墙壁10 feet时的滑动速率? 这题该怎麽解@@麻烦了... 我是设 y=26-2t x=√104t-t^2 找dx/dt ????? 这想法不知道对不对 然後就打结了 解不下去...麻烦板上的高手帮忙一下~@@ --

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