作者LuisSantos (^______^)
看板trans_math
标题Re: [微分] 89年考古题
时间Sat Apr 28 19:42:57 2007
※ 引述《j19880706 (smallpig)》之铭言:
: 这题我想好久 想不透 请大大帮我解题
: -1 ,
: If f(x)= 2X +cosX then (f ) (1) =
: 这题怎麽算阿
: 感谢大大教我
-1
令 g = f , 则 g(f(x)) = x
1
(g'(f(x)))(f'(x)) = 1 => g'(f(x)) = -------
f'(x)
f(x) = 2x + cosx => f'(x) = 2 - sinx
令 f(x) = 2x + cosx = 1 , 则 x = 0
f'(0) = 2 = 0 = 2
-1 1 1
(f )'(1) = ------- = ---
f'(0) 2
--
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