嗯.. 穷极无聊下跑去盖了 Community building, 然後又穷极无聊下跑去试 &start=X 偷看到了後面的分数列表.. 所以说它也是 4 个一组, 公式是 4 个一循环. n\组 a b c d 0 - - - 0 1 5 20 45 80 2 125 180 245 320 3 405 500 605 750 4 845 980 1125 1280 5 1445 1620 1805 2000 6 2205 2420 2645 2880 7 3125 3380 3645 3920 以 0 分的任务为编号 0, 5 分的为任务 1 来看.. 组 a 就是 任务编号/4 余 1 的; 组 b 就是 任务编号/4 余 2 的; 组 c 就是 任务编号/4 余 3 的; 组 d 就是 任务编号/4 余 0 的. a 组公式 => 5(4n-3)^2; n > 0 b 组公式 => 20(2n-1)^2; n > 0 c 组公式 => 5(4n-1)^2; n > 0 d 组公式 => 80n^2; n > -1 但 n = 3 时 y = 750 (唯一不合) ( 运算子优先程度: 括弧 > 幂次运算 > 乘除法 > 加减法.. ) 嗯.. 只能知道这里为止了, 关於钱的部份.. 0. The kindergarten needs 50.000￠ for a new playground. 1. The school needs new books for 100.000￠. 2. The church needs a new organ 500.000￠. 3. The mayor is asking for a small donation to the party funds. 1.000.000￠ should suffice. 4. The local pond has been polluted, the decontamination costs 10.000.000￠. 5. The community needs a new gym for 70.000.000￠. 6. Due to the particulate matter emission a new bypass had to be constructed for 150.000.000￠. 7. The theater is more than 100 years old and is in dire need of a renovation. Costs 550.000.000￠. 8. The rain forest needs to be reforested for 1.000.000.000￠. 9. An oil pipeline has burst and more than 1 million litres of oil have polluted the North Sea. Most part of the damage can be cleared for 5.000.000.000￠. 10. The research program FgEw, created to find a way to stop global warming, costs 15.000.000.000￠. 11. The FgEw's researchers have found a solution. Their program can be started for 65.000.000.000￠. 12. You will be awarded the golden Kapi-medal for extraordinary services to the community and the environment. 再往下就看不到字了, 不知道是不是因为缴的不够多, 还是说因为他们懒得掰了.. 乌鸦大概差.. 860 亿才能缴到那边.. 所以.. 所以.. 所以最少要等 443 天後才能缴到那边.. =______= 缴钱的部分数据太少, 乌鸦的慧根不足以看破其中隐藏的公式, 所以就先暂时这样子吧 ˊˇˋ --

※ 发信站: 批踢踢实业坊(ptt.cc) ◆ From: 118.168.37.1 ※ 编辑: Crow22312 来自: 118.168.37.1 (07/22 10:32)