We know in baseband, signal bandwidth equals (1+r)/2 times signal sampling r ate (PAM) or equals (1+r)/2 times signal bit rate (PCM) where r is the raise d cosine filter roll-off factor. And according to Nyquist sampling theorem, the sampling rate is twice of hig hest signal frequency. So the bandwidth is (1+r) times the highest signal frequency (PAM). Does this hold for passband? It seems as if W=M*R_{s}=M/T_{s} for MFSK where R_{s} is the symbol rate and T_{s} is the symbol time duration. How about the relationship between highest frequency and bandwidth of passba nd signaling? In another word, what's the sampling theorem of passband signa ling? --

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