作者JacksonCChen (B仔)
看板comm_and_RF
标题Re: [转录][问题] multipath
时间Thu Oct 27 14:10:00 2005
※ 引述《lovewa (走往开启知识的门...)》之铭言：
: ※ [本文转录自 Electronics 看板]
: 作者: persuasion (天天都很累) 看板: Electronics
: 标题: [问题] multipath
: 时间: Mon Oct 24 21:36:14 2005
: The maximum excess delay of the channel model is given
: by τN = N*Δτ. Therefore, for τN =100μs, and N=64
: we obtain Δτ =1.5625 μs . The maximum bandwidth that
: the SMRCIM model can accurately represent is equal to
: 1 / (2*Δτ) = 0.32 MHz <=== Why
: 为什麽 The maximum bandwidth 是这样算的呢 ?
: 看不懂....
就是取样定理 取样频率至少要是被取样讯号频率的两倍
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1F：推 lovewa:That's right，看来我之前的理解有些错误～感谢！ 10/27 15:38
2F：推 lovewa:是我想太多了，呵呵～ 10/27 15:40