※ 引述《aweila75 (David)》之铭言： : 2.A multiplattered hard disk is divided into 40 sectors and 400 cylinders. : There are four platter surfaces. The total capacity of the disk is 128MB. : A cluster consists of 4 sectors. The disk is rotating at a rate of 5400rpm. : The disk has an average seek time of 12 msec. : (a) what is the capacity of a cluster for this disk? : (b) what is the average access time before starting data transfer? : (c) what is the maximal disk transfer rate in bytes per second? : 想了很久，算不出来XD，高手请帮忙，感谢您。 (a)4*400*40 = 64000 sectors 一sector的capacity：128MB / 64000 = 2000 bytes 一cluster的capacity：2000*4 = 8000 bytes (b)（60*1000ms）/ 5400 = 11.11ms 11.11ms / 2＝5.55ms 12ms＋5.55ms = 17.55ms (c)回转一圈所须时间：（60*1000ms）/ 5400 = 11.11ms = 0.01111second 资料量:2000 bytes*40 = 80000 bytes maximal disk transfer rate： 80000 / 0.01111 = 7200720 bytes/second --

※ 发信站: 批踢踢实业坊(ptt.cc) ◆ From: 122.127.53.72 ※ 编辑: just1016 来自: 122.127.53.72 (04/22 22:55)