作者flashstar (闪亮的星)
看板TransCSI
标题Re: [问题] 政大92
时间Mon Jun 27 16:09:23 2005
※ 引述《darkhero (嘿吓～～HERO)》之铭言：
: ※ 引述《chen0404 (这个冬天会很暖)》之铭言：
: : A computer desinger designs a new computer that has 60 instructions in the
: : machine language and the maximal addresable memory
: : space is 512 MB .
: : (a)how many bits will be used in the instruction register to hold a
: : two-address instruction?
: : (b)what will be the decoder's input and output size used for IR(op)?
: : 想了很久...请问一下要如何解阿...感恩!!
: a.60 instruction=6 bits , 512MB=2^29=29 bits so 29*2+6=64 bits
: 2^5<60<2^6....所以6bits, hold a two-address 所以要29*2 (我理解的@@")
这里的 hold a two-address 指的是指令格式可以支援"两个"operand(运算元)
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