作者blablawawa (bla)
看板TransBioChem
标题[化学]化学平衡
时间Fri Jul 5 21:38:13 2013
1.
at equilibrium
CO2 + H2 → H2O + CO
←
2L vessel contains 0.48 mol each of CO2 and H2
and 0.96 mol each of H2O and CO
Kc=4
(1)how many moles of H2 and CO2 must be added to bring the concentration of CO
to 0.6 M ? (0.36 mol)
(2)how many moles of H2O must be removed to breing the concentration of CO to
0.6 M ? (1.008 mol)
不知道怎麽算?括号是答案。
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※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 140.122.167.59
1F：推 colagrange:初浓度[CO2]=[H2]=0.24M [H2O]=[CO]=0.48M 07/06 09:05
2F：→ colagrange:欲使[CO]=0.6M可知[CO]增加0.6-0.48=0.12M 07/06 09:07
3F：→ colagrange:增加反应物CO2和H2由勒沙特列知平衡向右，达新平衡 07/06 09:09
4F：→ colagrange:假设增加x mole,则等於浓度增加(x/2) M 07/06 09:11
5F：→ colagrange:反应物浓度变成0.24+（x/2) M 07/06 09:13
6F：→ colagrange:生成物[CO]增加量=反应物消耗量=0.12M 07/06 09:14
7F：→ colagrange:故平衡後浓度[CO2]=[H2]=0.24+(x/2)-0.12 07/06 09:16
8F：→ colagrange:[H2O]=[CO]=0.6，由Kc=4=[H2O][CO]/[CO2][H2]代入数据 07/06 09:19
9F：→ colagrange:得4=[0.6][0.6]/[0.24+(x/2)-0.12][0.24+(x/2)-0.12] 07/06 09:20
10F：→ colagrange:解得x=0.36mole-------这是第一题 07/06 09:21
11F：→ colagrange:第二题一样平衡後[CO]要=0.6就必须生成0.12M 07/06 09:23
12F：→ colagrange:移走[H2O]由勒沙特列知平衡向右达新平衡 07/06 09:25
13F：→ colagrange:设移走x mole,即移走(x/2)M又[CO]增加量=[H2O]增加量 07/06 09:32
14F：→ colagrange:得[H2O]新平衡浓度=0.48-(x/2)+0.12，[CO]=0.6 07/06 09:35
15F：→ colagrange:[CO2]和[H2]各消耗0.12平衡後[CO2]=[H2]=0.12 07/06 09:37
16F：→ colagrange:代入Kc=4=[0.48-(x/2)+0.12][0.6]/[0.12][0.12]，解x 07/06 09:39
17F：→ colagrange:得x=1.008 07/06 09:40
18F：→ colagrange:不好意思手机不好发文只好一条条步骤慢慢推，希望你看 07/06 09:41
19F：→ colagrange:得懂，祝你考试顺利，加油！ 07/06 09:42
20F：→ blablawawa:喔喔喔我看懂了 感谢认真的回答啊!!!!谢谢! 07/06 10:58
21F：推 mimipig:推c大A_A 07/08 15:37