作者siaxing (小锋子)
看板Statistics
标题[问题] 一题看不懂的英文统计题
时间Sun Apr 17 17:51:49 2011
女朋友的生统老师出了一题不知所云的考题
看了很久也看不懂,附上题目与解答
希望有神人帮帮忙解释一下
A researcher wanted to study the effects of mentoring on intelligence scores.
He wanted to know as a baseline what the average intelligence of his students
were relative to the general population. He used a standardized IQ test which
has a mean of 100 and standard deviation of 16. The 50 students in his study
scored an average of 102 on the IQ test. At what percentile of intelligences
is the average IQ of his students relative to his population ?
1. First find the standard error of the mean for a sample size of 50
,16/SQRT(50) = 2.26
2. How many standard errors are there between the observed sample mean and
the population mean: (102-100)/2.26 = .8849 standard errors.
3. The percent of area under the normal curve from negative infinity to
.8849 =81.2%, meaning the average intelligence of this set of students is
higher than 81.2% of all other samples of 50 students. It is also 31.2%
above an average IQ given this sample size.
Finally, we can use the 1-sample z-test to test hypotheses. The general
framework of Hypothesis testing will be covered in future lessons.
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比较大的问题是我看不懂 At what percentile of intelligences is the average
IQ of his students relative to his population ? 这句的意思看不太懂
解答中的第三点也看不出它想表达出的意思。81.2%的学生高於其他的学生?
这实在不懂阿
※ 编辑: siaxing 来自: 114.27.134.195 (04/17 17:59)
1F:→ yhliu:最後一句话是: 其学生的平均IQ相对於群体的百分位是多少? 04/17 18:51
2F:→ yhliu:因为是算 "平均IQ", 所以在算百分位时是以样本平均数的分布 04/17 18:52
3F:→ yhliu:为计算依据. 04/17 18:53
4F:→ yhliu:解答: 1. 计算出 Xbar 分布的标准差; 2. 计算出 Xbar 的 z值 04/17 18:54
5F:→ yhliu:3. 计算出这个 Xbar 观测值在其分布的百分位. 04/17 18:54
6F:→ siaxing:感谢,有比较了解一点 04/17 22:32