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标 题Re: 求助一题UMVUE...
发信站无名小站 (Thu Nov 3 16:36:59 2005)
转信站ptt!Group.NCTU!grouppost!Group.NCTU!wretch
※ 引述《kking222》之铭言:
> 令X1,...,Xn为一来自P(Xi=a-1)=P(Xi=a)=P(Xi=a+1)=1/3,且a为一整数.
> 证明没有非常数的g(a)有UMVUE.
Pf.
Let E[U(X)]=0 for all a
=> 1/3(U(a-1)+U(a)+U(a+1))=0 for all a
=> U(a-1)+U(a)+U(a+1)=0 for all a
If d(X) is UMVUE of g(a), then
E[d(X)U(X)]=0
=>1/3[d(a-1)U(a-1)+d(a)U(a)+d(a+1)U(a+1)]=0
=>d(a-1)U(a-1)d(a)U(a)+d(a+1)U(a+1)=0, for all U
Let U(a-1)=1, U(a)=-1, U(a+1)=0
then d(a-1)=d(a) for all a
=>d is constant.
and d is unbiase of g(a), so g(a) is constant.
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