作者cubefan (CF)
看板Rubiks
标题[闲聊] WCA 2016规则变动
时间Tue Apr 26 12:01:01 2016
内容转自刘睿钧在魔术方块社团的贴文
[2016 WCA规则异动]
与大家比较有相关的规则更改如下,先帮大家做简单整理,详细请参阅:
https://goo.gl/bP5IQs
1. 方块观察结束至启动计时器前,方块放在大垫以外的地方判罚为+2
2. 4代计时器可以正式在WCA比赛中使用
3. 任一面的Clock按钮不能为可辨认差异的,而Clock的还原状态不受按钮盖存在与否而
受影响
4. 还原方块时,身体的任何一个部位皆可以使用(单手和脚解例外)
5. 最小尺寸的大垫必须至少30公分宽(左到右),25公分长(上到下)
6. 额外还原机会建议在当下立即给予
7. 所有种类的贴纸皆可以在FMC当中使用
8. 人数限制可以用於设定比赛人数,并不限於个别项目
9. FMC解法与转乱步骤相似的相关规则澄清已经新增在规则里
10. 在累积还原时限的赛制中,若选手没有办法完成所有尝试,尚未完成的尝试会被记为
DNS
以上是更动的内容。
有兴趣了解2015与2016规则版本的所有细节差异可以参考这里~
https://goo.gl/MRwnPF
--------------------------------------------------
补充一下关於FMC的部分的更动
FMC部分
旧版- - E2e) The competitor's solution must not be directly derived from an
y part of the scrambling algorithm. Penalty: disqualification of the attempt (
DNF).
新版+ - E2e) The competitor's solution must not be directly derived from an
y part of the scramble sequence. Penalty: disqualification of the attempt (DNF
), at the discretion of the WCA Delegate.
WCA Guidelines有新增以下两条规则:
+- E2e+) [CLARIFICATION] Competitors must not derive solutions from any part o
f the scramble sequence, and solutions should not share significant parts with
the inverse scramble sequence.
+- E2e++) [EXAMPLE] Example of solutions that should result in a disqualificat
ion of the attempt (DNF): solutions beginning with the same 4 or more moves as
the inverse scramble sequence.
TNoodle 0.11.1版本也更新了FMC的scramble sequance
* The scramble generation process for Fewest Moves has been changed. Fewest Mo
ves scrambles are now longer and the scramble sequence is no longer directly r
elated to the puzzle state they produce. In particular, all scramble sequences
for Fewest Moves are padded with the moves "R' U' F" at the beginning and the
end.
有了这三步保护,基本上就很难跟解法相抵消了,若是有抵销的状况发生,按照Guildlin
es的解释就是以四步为判罚界线。
会有特别针对FMC提出更动是因为目前FMC avg WR的解法其中有一条和逆SC有11步相同,
经过WDC的判决这转改判为DNF。
大概就这样,祝大家玩方块愉快哈哈哈
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1F:→ rehearttw: 推! 04/26 19:21