※ 引述《RockLee (Now of all times)》之铭言： : 原始网址: : http://www.careercup.com/question?id=15381730 : 题目: : Given a document and a query of K words, : how do you find the smallest window that covers all the words at least once : in that document? : (given you know the inverted lists of all K words, that is, for each word, : you have a list of all its occurrrences). : Could someone propose an algorithm in O(n)? : 假设 occurrrences lists 是 sorted, 用 TreeMap 应可在 O(N*logK) 解决, : 一开始将每个 occurrrences list 最小的丢入 TreeMap 就可得到第一个 window, : (key = index in the document, value = the occurrrences list it belonged & its : index in that occurrrences list), : 之後将 TreeMap 最小的移除并加入同一个 occurrrences list 的下一个即可移动 : window, : 直到任一个 occurrrences list 耗完. : 但要在 O(N) 的时间内解决就想不出来了... : 不知道板上有没有人有什麽 idea? Sorry, I can't understand your writing. Also, the link seems to be wrong... Can you describe it, step by step. For example, there are only 3 words, (a,b,c) how are you going to find the window, for the document [b b a c b b b b c b b a] ? --

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