作者Yaowei (开心)
看板perl
标题Re: [问题] 也是另一个比对问题?
时间Tue Apr 10 19:56:48 2007
真的没人有什麽好方法可以建议= =
总觉得应该有点什麽规律或好的方法才对
若我先将 ACT with PTN PTN 用hash存成key
class2:ACT PTN PTN 存成value
再进行更进一步的处理呢？？？
以取得４个相对应的字呢？？？
※ 引述《Yaowei (开心)》之铭言：
: 若我知道 以下这些条件
: ACT with PTN PTN 与 class2:ACT PTN PTN
: ACT of PTN with PTN and PTN 与 class2:ACT PTN PTN
: ACT PTN and PTN 与 class2:ACT PTN PTN
: with PTN to ACT PTN . 与 class1:PTN ACT PTN
: PTN and PTN ACT with and PTN 与 class1:PTN ACT PTN
: . PTN ACT with PTN in 与 class1:PTN ACT PTN
: ACT of PTN PTN ACT 与 class3:PTN PTN ACT
: PTN in PTN ACT of PTN ACT by 与 class3:PTN PTN ACT
: ACT with PTN PTN ACT 与 class3:PTN PTN ACT
: 例子一：
: ACT with PTN PTN 想取到下面()内的字
: ==> () ACT (with) PTN () PTN ()
: 即我想取得 class2:ACT PTN PTN 的前後与中间两个范围内的字，若没有字则以空白代替
: ==> ($left, $middle1, $middle2, $right) = ("","with","","");
: 例子二：
: with PTN to ACT PTN . 与 class1:PTN ACT PTN
: ==> (with) PTN (to) ACT () PTN (.)
: ==> ($left, $middle1, $middle2, $right) = ("with","to","",".");
: 例子三：
: ACT of PTN PTN ACT class3:PTN PTN ACT
: ==>(ACT of) PTN () PTN () ACT ()
: ==> ($left, $middle1, $middle2, $right) = ("ACT of","","","");
: 请问有人可以解决或回答吗^^?感谢:)
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