作者lysosome (遇到善心人士^^)
看板PHP
标题[请益]fopen
时间Mon Nov 28 23:54:38 2005
这是一个"消息公告"的小程式
每次要发布消息的时候都会出现下面的失败通知 Orz
Warning: fopen(data.dat) [function.fopen]: failed to open stream:
Permission denied in/home/STUDENT/public_html/test/result.php on line 50
Warning: fwrite(): supplied argument is not a valid stream resource in
/home/STUDENT/public_html/test/result.php on line 51
Warning: fclose(): supplied argument is not a valid stream resource in
/home/STUDENT/public_html/test/result.php on line 52
==
以下是result.php 的第50~52行
$f=fopen("data.dat","a+");
fwrite($f,$main);
fclose($f);
可以教教我该怎麽修改吗
因为看不懂,怎麽看都好像对又不对的样子= =b
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 134.208.34.12
1F:推 ottokang:伺服器的档案权限设定有问题 11/29 00:08
※ 编辑: lysosome 来自: 134.208.34.12 (11/29 15:16)