这个ch.的习题的内容翻译还好,不过难题好多,加油!!!(至少ch.7比较少XDDD) 如果大家看到题目跟翻译有以下问题: 1.翻译错误,文意不通 2.原文有漏 3.其他人为错误(其实是我想不到还有什麽错误XD) 请到msn通知我或者在见面的时候再说也可以la!!! 废话少说,请看!! 题号浅蓝色为难题 <-->为双箭头(可逆反应) ch.8 exercises 94. The copper(I) ion forms a chloride salt that has Ksp = 1.2 x 10^-6. Copper(I) also forms a complex ion with Cl-: Cu+(aq) + 2Cl-(aq) <--> CuCl2-(aq) K = 8.7 x 10^4 a. Calculate the solubility of copper(I) cholride in pure water. (Ignore CuCl2- formation for part a.) b. Calculate the solubility of copper(I) chloride in 0.10 M NaCl. 94.已知亚铜离子可形成氯化盐,其Ksp = 1.2 x 10^-6.亚铜离子亦可以与氯离子形成一复 杂离子: Cu+(aq) + 2Cl-(aq) <--> CuCl2-(aq) K = 8.7 x 10^4 a.算出在纯水中氯化亚铜的的溶解度.(该小题忽略CuCl2-的形成.) b.算出在0.10M的氯化钠溶液中,氯化亚铜的溶解度. 103. One method for determining the purity of aspirin (empirical formula, C9H8O4) is to hydrolyze it with NaOH solution and then to titrate the remaining NaOH. The reaction of aspirin with NaOH is as follows: C9H8O4(s) + 2OH-(aq) --Boil , 10 min--> C7H5O3-(aq) + C2H3O2-(aq) + H2O(l) Aspirin Salicylate ion Acetate ion A sample of aspirin with a mass of 1.427 g was boiled in 50.00 mL of 0.500 M NaOH. After the solution was cooled, it took 31.92 mL of 0.289 M HCl to titrate the excess NaOH. Calculate the purity of the aspirin. What indicator should be used for this titration? Why? 103.一个测定阿士匹灵(经验所得的分子式为C9H8O4)的纯度的方法:使用氢氧化钠溶液令 其水解,然後用滴定法测量剩余的氢氧化钠.阿士匹灵跟 氢氧化钠的化学反应如下: C9H8O4(s) + 2OH-(aq) --煮沸10分钟--> C7H5O3-(aq) + C2H3O2-(aq) + H2O(l) 阿士匹灵 水杨酸离子 醋酸离子 现在用质量为1.427g的阿士匹灵样本跟浓度为0.500M的氢氧化钠50.00mL共沸.待溶液冷却 後,以浓度为0.289M的盐酸跟过量的氢氧化钠滴定,用去该盐酸31.92mL.计算出阿士匹灵的 纯度.在滴定的过程中,应使用什麽指示剂?试解释之. 123. A buffer is made using 45.0 mL of 0.750 M HC3H5O2 (Ka = 1.3 x 10^-5) and 55.0 mL of 0.700 M NaC3H5O2. What volume of 0.10 M NaOH must be added to change the pH of the original buffer solution by 2.5%? 123.有一缓冲液由0.750M的丙酸(Ka = 1.3 x 10^-5)45.0mL以及0.700M的丙酸钠55.0mL所 制成.问需要加入多少体积浓度为0.10M的氢氧化钠使该缓冲液原来的pH值改变了2.5%? 125. For solutions containing salts of the form NH4X, the pH is determined by using the equation pH =[ pKa(NH4+) + pKa(HX) ] / 2 a. Derive this equation.(Hint: Review Section 8.7 on the pH of solutions containing amphoteric species.) b. Use this equation to calculate the pH of the following solutions: ammonium formate, ammonium acetate, and ammonium bicarbonate. See Appendix 5 for Ka values. c. Solutions of ammonium acetate are commonly used as pH = 7.0 buffers. Write equations to show how an ammonium acetate solution neutralizes added H+ and OH-. 125.有一溶液包含了这种盐:NH4X,其pH值取决於以下算式: pH =[ pKa(NH4+) + pKa(HX) ] / 2 a.推导该算式.(提示:回顾Section 8.7的the pH of solutions containing amphoteric species部分,在书的第315页.) b.利用该算式计算以下溶液的pH值:甲酸铵,醋酸铵以及重碳酸铵(即碳酸氢铵).请到附录5 查出它们各自的Ka值. c.醋酸铵溶液通常被用作为pH值=7.0的缓冲液.写出化学方程式去表达当加入酸,以及加入 硷的时候,醋酸铵溶液如何各自去中和它们. 127. a. Calculate the molar solubility of SrF2 in water, ignoring the basic properties of F-. (For SrF2, Ksp = 7.9 x 10^-10.) b. Would the measured molar solubility of SrF2 be greater than or less than the value calculated in part a? Explain. c. Calculate the molar solubility of SrF2 in a solution buffered at pH = 2.00. (Ka for HF is 7.2 x 10^-4.) 127. a.算出在纯水中SrF2的莫耳溶解度,计算时要忽略F-引起硷性的特性.(SrF2的Ksp = 7.9 x 10^-10.) b.试估量SrF2的真实莫耳溶解度应大於还是小於a小题所计出来的值,并解释之. c.算出在pH=2.00的缓冲液中SrF2的莫耳溶解度.(HF的Ka为7.2 x 10^-4.) 129. a. Show that the solubility of Al(OH)3, as a function of [H+], obeys the equation: S = { [H+]^3 x Ksp / (Kw)^3 } + { K x Kw / [H+] } where S = solubility = [Al3+] + [Al(OH)4-] and K is the equilibrium constant for Al(OH)3(s) + OH-(aq) <--> Al(OH)4-(aq) b. The value of K is 40.0 and Ksp for Al(OH)3 is 2 x 10^-32. Plot the solubility of Al(OH)3 in the pH range 4-12. 129. a.证明氢氧化铝的溶解度,实际上是遵从一条以[H+]为函数的算式: S = { [H+]^3 x Ksp / (Kw)^3 } + { K x Kw / [H+] } 在上式中,S = 溶解度 = [Al3+] + [Al(OH)4-],以及K为以下平衡反应之平衡常数: Al(OH)3(s) + OH-(aq) <--> Al(OH)4-(aq) b.已知K值为40.0以及Al(OH)3的Ksp为2 x 10^-32.用图表表示出氢氧化铝在pH值为4至12 的范围内的溶解度. 若要转贴,必先得到我同意!!! ※ 编辑: ryo2006 来自: 140.112.250.56 (10/26 13:19) ※ 编辑: ryo2006 来自: 140.112.250.56 (10/26 13:21) ※ 编辑: ryo2006 来自: 140.112.250.56 (10/26 13:22)