作者her0418 (晓枫)
看板NTU-Exam
标题[试题] 101下 石百达 财务工程入门 期中考
时间Sun Apr 28 16:35:49 2013
课程名称︰财务工程入门
课程性质︰系选修
课程教师︰石百达
开课学院:管理学院
开课系所︰财务金融学系
考试日期(年月日)︰102/4/26
考试时限(分钟):160分钟
是否需发放奖励金:是
(如未明确表示,则不予发放)
试题 :
每题10分
CA:American call PA:American put PE:European put
1.Prove So-K<=CA-PA<=So-Kexp(-rT)
(小於等於)
2.A call with a strike price of $60 costs $6. A put with the same strike price
and expiration date costs $4. Construct a table shows the profit form a
straddle. For what range of stock prices would be the straddle lead to a
loss?
3.A company's stock price is $50 and 10 million shares are outstanding. The
company is considering giving its employees 3 million at-the-money 5-year
call options. Option exercises will be handled by issuing more shares. The
stock price volatility is 25%, the 5-year risk-free rate is 5%, and the
company does not pay dividends. Estimate the cost to the company of the
employee stock option issue.
4.Suppose that x is the yield to maturity with compounding on a zero-coupon
bond the palys off $1 at timeT. Assume that x follows the process
dx=a(xo-x)dt+sxdz,
where a,x0,and s are positive constants, and dz is Wiener Process
What is the process followed by the bond price?
5."A box spread comprises four options. Two can be combined to create a long
forward position and two can be combined to create a short forward position."
Explain this statement.
6.Assume that a non-dividend-paying stock has an expected return of r and a
volatility of (sigma). An innovative financial institution has just
announced that it will trade a security that pays off a dollar amount
equivalent to lnST at time T.
(a) Use risk-neutral valuation to calculate the price of the security at
time t in terms of the stock price, S, at time t.
(b) Confirm that your price satisfies the differential equation
df/dt+rs(df/ds)+0.5(sigma)^2*S^2*(d^2f/ds^2)=rf
7.不发股利情形下,at-the-money European call 和European put 何者价值较高?
为什麽?
8.用几何布朗运动描述股价过程有何优缺点?
9.请用package 概念证明put-call parity
10.在不发股利情形下,假设执行价格微函数:K(t)=Kexp(r(t-to))
t0为起始时间、t为现在时间,试证明
(a)PE(t)>=K(t)-S(t)
(b)PE(t)=PA(t)
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