作者twc94 (蔡哲)
看板NTU-Exam
标题[试题] 100下 陈逸聪 物理化学 期中考
时间Mon Jun 25 23:34:41 2012
课程名称︰物理化学二
课程性质︰系必修
课程教师︰陈逸聪
开课学院:理学院
开课系所︰化学系
考试日期(年月日)︰2012/4/22
考试时限(分钟):120 (open book)
是否需发放奖励金:yes
(如未明确表示,则不予发放)
试题 :
1.Consider the transformation from Cartesian coordinates to plane polar
coordinates where
2 2 0.5 -1
x=rcosθ y=rsinθ r=(x +y ) θ=tan (y/x) (1)
If a function f(r,θ) depends upon the polar coordinates r and θ, then
the chain rule of partial differentiation says that
(df/dx) = (df/dr) (dr/dx) +(df/dθ) (dθ/dx) (2) y │
y θ y r y │ P(x,y)or
│ / P(r,θ)
(df/dy) = (df/dr) (dr/dy) +(df/dθ) (dθ/dy) (3) │ /
x θ x r x │ /
│/
└─────────
x
For simplicity, we will assume r is constant so that we can ignore terms
involving derivatives with respect to r. In other words, we will consider
a particle that is constrained to move on the circumference of a circle.
This system is sometimes called "a particle on a ring."
(a) Using equation 1 and 2, show that
(df/dx) = (-sinθ/r)(df/dθ) and (df/dy) = (cosθ/r)(df/dθ)
y r x r
(r fixed)
(b) Now apply equation 2 again to show that
2 2 2 2 2 2 2
(d f/dx ) =(sinθcosθ/r )(df/dθ) +(sin θ/r )(d f/dθ ) (r fixed)
y r r
Similarly, show that
2 2 2 2 2 2 2
(d f/dy ) =(sinθcosθ/r )(df/dθ) +(cos θ/r )(d f/dθ ) (r fixed)
x r r
and that
2 2 2 2 2 2 2 2
▽ f=( d f/dx ) +(d f/dy) → (1/r )(d f/dθ ) (r fixed)
r
(c) Now show that the Schordinger equation for a particle of mass m
constrained to move on a circle of radius r is
2 2
-(h/4πI)(d Ψ(θ)/dθ ) = EΨ(θ) 0≦θ≦2π
2
where I = mr is the moment of inertia
2.As derived above, the Schordinger equation for a particle on a ring is
2 2
-(h/4πI)(d Ψ(θ)/dθ ) = EΨ(θ) 0≦θ≦2π
Solve the eigenfunctions and eigenvalues for this system
3.For a particle in a one-dimensional box of a length a, show that <p> = 0
for all quantum states.
4.Many proteins contain metal porphyrin molecules. The general structure of
the porphyrin molecule is drawn on the right hand side, This molecule is
planar and so we can approximate the π electrons as being confined
inside a square. (porphyrin图省略ˊˇˋ)
(a) What are the energy levels and degeneracies of a particle in a square
of side a?
(b) The porphyrin molecule has 26 π electrons. If we approximate the
length of molecule by 1000pm, then what is the predicted lowest energy
absorption of the porphyrin molecule (1/cm) ?
5. 12 16
C O is an example of a stiff diatomic molecule, and it has a vibration
frequency of 2170 (1/cm).
(a) What is the value of the force constant k?
(b) What is the value of the standard deviation Δx in the internuclear
distance?
(c) What is the standard deviation Δpx of the momentum of the vibrational
motion?
(d) Check that the product ΔxΔpx yields h/4π in accordance with the
Heisenberg uncertainty principle.
6. 12 16
The C O molecule has an equilibrium bond distance of 112.8pm. Calculate
(a)the reduced mass and (b)the moment of inertia. (c)Calculate the
wavelength of the photon emitted when the molecule makes the transition
from l=1 to l=0 using equation 9.144 for the energy levels.
7.In a hydrogen like atom in the 1s state, there is a difference between the
average distance (<r>) between the electron and the nucleus and the most
probable distance (r mp) between the electron and the nucleus.
(a)Derive the expression for the average distance <r> between the electron
and the nucleus
(b)Derive the expression for the most probable distance r mp
8. m
Using explicit expressions for Y (θ,φ),
l
1 2 0 2 -1 2
(a)Show that │Y (θ,φ)│ + │Y (θ,φ)│ + │Y (θ,φ)│ = constant
1 1 1
l m 2
This is a special case of the general theorem Σ│Y (θ,φ)│ = constant
-l l
known as Unsold's theorem.
(b)What is the physical significance of this result?
9.(a)Calculate the probability that a hydrogen 1s electron will be found
within a distance 2a from the nucleus.
0
(b)Calculate the radius of the sphere that encloses a 90% probability of
finding a hydrogen 1s electron
10.In chapter 10, we learned that if Ψ1 and Ψ2 are solution of Schordinger
equation that have the same energy En, then c1Ψ1+c2Ψ2 is also a
solution. Let Ψ1=Ψ210 and Ψ2=Ψ211 (see table 10.1)
2 2
(a) What is the energy corresponding to Ψ=c1Ψ1+c2Ψ2 where c1 +c2 =1
(b) What does this result tell you about the uniqueness of the three p
orbitals, px, py, and pz
11.The spin function α and β cannot be expressed in terms of spherical
harmonics, but they can be expressed as column matrices:
┌ 1 ┐ ┌ 0 ┐
α=│ │ and β=│ │
└ 0 ┘ └ 1 ┘
The spin operator can be represented by the following Pauli matrix:
^ 1 ┌ 1 0 ┐ ^ ^
Sz = ─│ │ Show that Szα=0.5α and Szβ= -0.5β
2 └ 0 -1 ┘
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