作者clxy (clxy)
看板NTU-Exam
标题[试题] 98下 陈永耀 控制系统 期中考
时间Sun Apr 25 21:48:44 2010
课程名称︰ 控制系统
课程性质︰ 电机系系选修
课程教师︰ 陈永耀
开课学院: 电资学院
开课系所︰ 电机工程学系
考试日期(年月日)︰ 2010/04/22
考试时限(分钟): 2:20pm-5:20pm
是否需发放奖励金: 是
(如未明确表示,则不予发放)
试题 :
(Note: All answers should provide adequate explanations. Simple "yes" or "no"
will not earn points)
1. Please five an example of biological or social closed-loop control systems,
and draw its block diagrams with the basic building blocks. (20%)
(Note: please specify all the variables with typical notations and their
corresponding meanings in your example. For example, the output "y" maybe
the "velocity" of the motor.)
2. (a)please give the description on the design procedures of a PID controller.
(b)Specifically, what should we do if the PID control system is having a
more-than expected steady-state error? (10% each)
3. Given the desgin specification for a closed-loop control system:
i)overshoot<15% ii)rise time<0.1s iii)settling time <3s
please identify the corresponding specifications in terms of
a)the damping ratio and the neutral frequency.(5%)
b)the pole locations(5%)
c)for the typical P-control feedback control system with open-loop transfer
function of G(s)=100/(s^2+10s+100)(s+100) and K=50, please estimate the
specifications (i)(ii)(iii) and give the corresponding damping ratio,
neutral frequency, and pole locations. (5%)
d)please answer as in (c) except with K=2000 (5%)
4. Please specify the stability conditions of the following systems with pole/
zero locations at the following positions:
a) poles at -1,-2+10j,-2-10j; zeros at -2,-10 (5%)
b) -1, 2+10j, 2-10j; 2, 10 (5%)
c) -1,-2+1-j,-2-10j,0; -2, 10 (5%)
d) -1,-2+10j,-2-10j,0,0; 2,-10 (5%)
5. Given the close-loop system in figure1, please answer the following
questions:
a) please derive the transfer function Y(s)/R(s) (4%)
b) please determine if the stability of the closed-loop system with K=1 8%
C) please determine if the stability of the closed-loop system with K=10 8%
┌───────────────┐
+│ │
┌─┐ + ↓ 6 s-4 │ +
│1├─→Σ─→K─→Σ─→ ──── ─┬→ ─── ─┴─→Σ──┬→ Y(s)
└─┘ ↑- + s^2+10s+40 │ s+1 ↑+ │
R(s) │ │ 1 │ │
│ └→ ───── ──┘ │
│ 2s^2+4s+4 │
│ │
└───────────────────────────┘
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1F:推 ketsu1109 :已收入 04/26 23:55
2F:→ aibltjv :谬误有点多...0打成负号差点看不懂= = 11/14 01:24