作者Sgenius (*)
看板NTU-Exam
标题[试题] 96下 古慧雯 赛局论 期中考
时间Sat Apr 19 14:35:45 2008
课程名称︰赛局论
课程性质︰选修
课程教师︰古慧雯
开课学院:社科院
开课系所︰经济系
考试日期(年月日)︰2008/4/18
考试时限(分钟):110
是否需发放奖励金:是
(如未明确表示,则不予发放)
试题 :
总分42分。答题须附说明,未做解释的答案概不计分。
1. Consider the following game
1
A ╱╲ B Regarding the outcome, player 1's preference ordering
╱ ╲ is: W >1 D >1 L, and player 2's preference
D 2 ordering is: L >2 D >2 W
a ╱╲ b
╱ ╲
W L
(a) (2 points) What is the value of the game?
(b) (4 points) Please write out the strategic form of the game, and find the
saddle point of the strategic form.
(c) Now, turn to consider the following zero-sum game. The payoff in the
following strategic form is the payoff to the row player. Each player only
considers to use a pure strategy.
| a | b
----------
A | 1 | 0
B | 0 | 1
i. (2 points) What is row player's security level?
ii. (2 points) You could verify that different from the game in part (b),
there is no saddle point in this zero-sum game. But at the beginning of
this course, didn't we always talk about the existence of value in a
strictly competitive game? So this zero-sum game must violate some
assumption that is used to prove the existence theorem. Which assumption
does it violate?
2. (6 points) Consider the game Nim. There are 4 rows of matches on the table.
The first row has 10 matches, the second row has 15 matches, the third row
has 2 matches, and the fourth row has 3 matches. Two players take turns to
take matches. When it is his turn, a player has to select a row and take n
matches from that row, n>0. The player that has no more match to take loses.
Which player has a winning strategy? And how should this player play in his
first round?
3. (6 points) Consider the game Parchessi. Different from the rule in the text
book, a player will roll a fair dice to decide his move. If the number of
dice turns out to be smaller than, or equal to, 4, the player could move his
counter two squares or pass. Otherwise, the player could move his counter
one square or pass. In the following, the left-most board shows the route
of each player. We also depict two possible positions A and B when the X
player is about to roll the dice. Please calculate his winning probability
in each position.
┌─┬─┐ A ┌─┬─┐ B ┌─┬─┐
│X╪╗│ │ │X│ │X│ │
├─┼╫┤ ├─┼─┤ ├─┼─┤
│←╪╣│ │ │O│ │ │O│
├─┼╫┤ ├─┼─┤ ├─┼─┤
│O╪╝│ │ │ │ │ │ │
└─┴─┘ └─┴─┘ └─┴─┘
4. A, B and C sit in a circle. Each of them wears a hat that is either white or
black. A person could see the hats of the other 2 persons, but not his own.
They are told that at least one of them wears a white hat. D will start to
count time, and every one minute (long enough for their mental calculation),
the one who realizes the color of his hat will raise a hand.
(a) (2 points) How many different states of the world are in the universe?
(b) The true state (ω*) is that A and B wear white hats, and C wears a
black hat.
i. (2 points) Before D counts time, what is A's possibility set of ω*,
Pa(ω*)?
ii. (2 points) After the first minute, who will raise hand?
iii. (2 points) After the second minute, who will raise hand?
iv. (2 points) After the third minute, who will raise hand?
5. (10 points) Consider a finite universe Ω. Let ω denote an element of Ω.
Let K and P denote the knowledge operator and the possibility operator,
respectively. P(ω) is the possibility set. Consider the following axioms:
(p0) Pψ=ψ
(p1) P(E∪F)=PE∪PF
(p2) E≦PE (注: ≦为集合符号)
(p3) (P^2)E≦PE
(p4) PKE≦KE
and the additional result: P(ω) = P{ω}, all ω属於Ω
Consider an event E ≦ Ω, E≠ψ and E is NOT a truism. Please compare the
number of elements in E, KE and PE. (If you use additional result or
theorem, please state it clearly.)
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