Consider a demand-paging system with a paging disk that has an average access and transfer time of 20 milliseconds.Addresses are translated through a page table in main memory, with an access time of 1 microsecond per memory access. Thus, each memory reference through the page table takes two accesses. To improve this time, we have added an associative memory that reduces access time to one memory reference, if the page-table entry is in the associative memory. Assume that 80 percent of the accesses are in the associative memory and that, of the remaining, 10 percent (or 2 percent of the total) cause page faults.What is the effective memory access time? 恐龙本习题 跟95政大的考题类似 但给的答案 EAT = (0.8) × (1 us) + (0.1) × (2 us) + (0.1) × (5002 us) = 501.2 us = 0.5 ms 其中 5002us 满怪的 我算的是 应该2*20 ms + 2*1 us =40002us 有高手可以解释整个架构吗? 谢谢! --

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