可以请问一下，关於多执行绪在恐龙书上，有几行没有很了解他的意思，是否有人可以帮 忙解释一下，谢谢。 Assuming that the threads are part of the same larger process, the kernel needs to write the program counter, register set and stack of the outgoing thread to a backing store, and switch to point to the PCB of the incoming thread (to look at the new values in the PC, register and stack). when performing a context switch between processes, we must update additional information including the code block, the file pointers, the memory. --

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