作者coolne (酷ㄋㄟ)
站内Grad-ProbAsk
标题[理工] [计组]-RAID
时间Sun Sep 27 00:58:38 2009
看到这一段有点看不懂
内文是
As the number of disks grows by 1
当DISK多一颗
the number of access required to calculate a parity word in RAID 3
also grows by 1.
在RAID 3中，需要计算parity的disk也会多1颗
in contrast, RAID 4 and 5 continue to access only existing
values of data being stored.
这段看不懂
thus,as the number of disk grows , RAID 3 performance will continue to
degrade while RAID 4 and 5 will remain constant.
当disk数一直增加，RAID3效能会一直掉，RAID 4 and 5 会维持固定
怎麽翻都怪怪的 麻烦大家指点了
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