作者Ollin (tail36)
看板Grad-ProbAsk
标题Re: [问题]95年北科计概~
时间Thu Mar 26 11:39:16 2009
※ 引述《lu1227 (lu)》之铭言：
: 题目:Suppose that a certain software product has a mean time
: beteween failures of 10,000 hours and has a mean time to
: repair of 20 hours. If the product is used by 100 customers,
: what is ites availability?
: 1)80.2%
: 2)90.1%
: 3)98.9%
: 4)99.8%
: 5)100%
: 我在网路上也找不到算法~麻烦各位了~感温~~
网路上很难找而已...话说我临时抱佛脚(应该没啥用
Availability = MTBF/(MTBF+MTTR)
MTBF: mean time between failure
MTTR: mean time to repair
Availability = 10,000/(10,000+20) = 0.998---------(D)
MTBF: 10,000
MTTR: 20
100人 就 不知道有什麽用?(又有分并连串联的
资料据说是来自CCDP思科...
有错请指证~^ ^
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1F：推 lu1227:感谢你的回答><~~ 03/27 00:14