作者jjhgfr (CZ=WZ)
看板GMAT
标题Re: [问题] PP 数学请教
时间Thu Sep 27 11:15:41 2007
※ 引述《KMI (无奈)》之铭言:
: DS: 刚刚模考做到
: A certain one-day seminar consisted of a morning session and an afternoon
: session. If each of the 128 people attending the seminar attended at least
: one of the two sessions,
: how many of the people attended the morning session only?
: 1) 3/4 of the people attended both sessions.
: 2) 7/8 of the people attended the afternoon session.
: 答案: B
假设参加早场的人为A 午场的人为B
则128人指的是 A+B (AUB)
1. 为 AnB (交集) 只能推得参加的总人数 A+B-(AnB)=参加总人数
2. 7/8参加午场 所以1/8参加早场 128* (1/8) = 16
答案为B
: A certain city with a population of 132,000 is to be divided into 11 voting
: district, and no district is to have a population that is more than 10%
: greater than the population of any other district. What is the minimum
: possible population that the least populated district could have?
: 1. 10700
: 2. 10800
: 3. 10900
: 4. 11000
: 5. 11100
: 答案: D
题目指出 没有任合一个地区会超出另一个地区 10%人口
假设一地区最少人口为a 别的地区那最多人口就是 a* 110% = 1.1a
a有最小值的情况---> 其他所有10个地区都是刚好超出a有10%的人口数
所以 (1.1a+1.1a+.....1.1a)+a = (1.1a)*10 + a = 132000
解得a为11000人
恩~ 我是这样想的 囧>
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 61.216.196.118
※ 编辑: jjhgfr 来自: 61.216.196.118 (09/27 11:16)
1F:→ KMI:3Q~ 09/27 21:42