※ 引述《chestnut42 ()》之铭言： : 来源: 台大黄贞颖老师98年考古题 : 科目:个题经济学 : 问题: : 1. Every weekend, Eliette goes to an amusement park (FunLand) and spends her : entire budget of $40. There are only two things she spends her money on : there: roller coaster cost $3/ride and ice cream cost $2/cone, Eliette buys : 8 rides and 8 cones. : (a)(10 points) In week 2, the FunLand changes its price to $2/ride and : $3/cone. Is it possible for Eliette to be strictly worse off? Is it : possible for Eliette to be strictly better off? Could she be exactly as : well off as before (indifferent)? Explain. 画预算线，初始价格时他选择{8，8} 改变价格後，他也买得起{8，8}的组合 但有更多选择 所以效用大於等於初始效用 EX U = min {Qr,Qc} 相等 U = Qr^3Qc^2 效用增加 : In week 3, FunLand changes its prices back to $3/ride and $2/cone (the same : as in week 1). But a new amusement park, Bob's wonderland, opens. At Bob's : wonderland, roller coaster rides and ice cream cones both cost $2. If : Eliette went there, she would buy 15 rides and 5 cones. To compete, FunLand : offers the following promotion: any customer who spend at least $40 will : get $15 worth of free coupons to spend on either roller coaster rides or ice : cream cones. : (b)(15 points) Would Eliette rather go to FunLand or to Bob's wonderland? : Explain. wonderland 的价格消费{15，5} 此时也消费得起 {8，8} 优於初始funland条件 但若与 3Qr + 2Qc = 55 相比，funland 优惠条件买不起{15，5}的组合 消费40买了{8，8}後，3Qr + 2Qc = 55的限制范围是{13，8} 与 {8，15.5}的区域 互相有对方买不起的组合 => 无法比较优劣 视效用函数而不同 我是以比较福利的章节来看，不过不太会用电脑画图...所以 ... 有错还请多指教 : 我的想法: : 虽然分别知道两小题的预算限制， : (a) 3x+2y=40 : 2x+3y=40 : (b) 2x+2y=40 : 3x+2y=55 : 但是在题目没有告知效用函数的情况下， : 不知道该怎麽样找出，她会比较分别偏好哪个;; : 麻烦板友解答了 : 谢谢:) --

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