作者welly (insight)
看板Economics
标题Re: [请益] 混合赛局
时间Thu Oct 18 00:20:14 2007
To be exact, assume that all firms are risk-netural.
Assume first that there are two existing firms.
We will check this assumption later. Denote them as 1 and 2.
Since we are interested in symmetric strategies,
it is sufficient to consider firm 1's strategy only.
Simple obsveration: there is no pure-strategy Nash equilibrium. (why?)
Define F(x)=prob.{firm 2's price <= x} to be firm 2's
equilibrium mixed strategy, and assume that F(x) is differentiable
with support [a,b], where 0 <= a < b <= r.
Given F(.), if firm 1's price is x, his expected profit is
π(x)= x{U+[1-F(x)]I}-k , if x>0;
0 , if x=0. (1)
(x=0 corresponds to no production)
To justify the symmetric mixed-strategy F(x), we must have
π'(x)=0 for all x belongs to [a,b]. (2)
Moreover, to justify that no other firm wants to enter
the market, we must have
π(a)=π(b)=π(0)=0 (3)
Note that equations (1) and (2) together generate the following
differential equation
[xF(x)]'=1+ U/I. (4)
From (3), one should be able to find a and b, which provide
the boundary condtions of (4).* The rest of the problem follows.
*Here I try to endogenize the number of existing firms, and
find it is related to the fixed cost k and reserve price r.
The condtion for exactly two firms existing in the market is
rU-k=0, provided by b=r. (why b should be r?)
On the other hand, if the number of firms is exogenous, then
(3) can be modified to provide a lower bound of a (b=r still),
so the boundary condition becomes
π(b)=rU-k. (5)
For those who are interested in more complete results of the model,
please refer to Varian (1980), A Model of Sales.
※ 引述《esail (我)》之铭言:
: 考虑存在於寡占市场中的厂商皆进行价格竞争,
: 且每家厂商的边际成本为0、固定成本为k。
: 现在市场上有两种类型的消费者,
: 第一种是informed consumers:能够知道最便宜的产品在哪一家store
: 第二种是uninformed consumers:只能随机的选择store消费
: 而且第一种消费者的数量为I,第二种消费者的数量为2U
: 假设每一家厂商在某一期间内确定能招揽到数量U的第二种消费者,
: 若想吸引到第一种消费者,产品的定价则必须是市场上的最低价
: 而不论是第一种还是第二种消费者,
: 当价格低於保留价格r时,才会购买1单位的产品,否则不会购买。
: 试问,在每一家厂商都采取相同的策略下,此赛局的Nash均衡为何?
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 122.124.100.59
1F:推 publius:推一下 welly 大 220.139.52.130 10/18 00:46
2F:推 wands:推一下 140.112.215.26 10/18 00:47
※ 编辑: welly 来自: 122.124.103.170 (10/18 07:02)
3F:推 esail:大大大大推,谢谢您,您真是我的大恩人^^140.119.210.172 10/18 11:29
※ 编辑: welly 来自: 140.109.160.13 (04/02 11:51)